{"result":{"text":"therefore space space space space space 1 over C equals fraction numerator 1 over denominator 4 pi epsilon subscript 0 a end fraction plus fraction numerator 1 over denominator 4 pi epsilon subscript 0 b end fraction rightwards double arrow 1 over C equals fraction numerator 1 over denominator 4 pi epsilon subscript 0 a end fraction open parentheses 1 over a plus 1 over b close parentheses\nspace space space space space space space space space space space C equals fraction numerator 4 pi epsilon subscript 0 a b over denominator a plus b end fraction equals fraction numerator 4 pi epsilon subscript 0 over denominator 1 over a plus 1 over b end fraction"},"status":"ok"}