{"result":{"text":"If space 5 cos to the power of negative 1 end exponent open parentheses fraction numerator 1 minus x squared over denominator 1 minus x squared end fraction close parentheses plus 7 s i n to the power of negative 1 end exponent open parentheses fraction numerator 2 x over denominator 1 plus x squared end fraction close parentheses minus tan to the power of negative 1 end exponent open parentheses fraction numerator 2 x over denominator 1 minus x squared end fraction close parentheses minus tan to the power of negative 1 end exponent x equals 5 pi comma then space x space is space equalto"},"status":"ok"}