{"result":{"text":"therefore E subscript 1 plus E subscript 2 equals fraction numerator 1 over denominator 4 pi epsilon subscript 0 end fraction fraction numerator 2 Q over denominator d squared end fraction plus fraction numerator 1 over denominator 4 pi epsilon subscript 0 end fraction fraction numerator 2 Q over denominator d squared end fraction equals fraction numerator 1 over denominator 4 pi epsilon subscript 0 end fraction fraction numerator 4 Q over denominator d squared end fraction equals E subscript 3"},"status":"ok"}