{"result":{"text":"Let space f colon R rightwards arrow R space be space such space that space f open parentheses 1 close parentheses equals 3 comma space and space f apostrophe open parentheses 1 close parentheses equals 6. Then comma limit as x rightwards arrow 0 of space open square brackets fraction numerator f open parentheses 1 plus x close parentheses over denominator f open parentheses 1 close parentheses end fraction close square brackets equals"},"status":"ok"}