{"result":{"text":"begin mathsize 14px style e to the power of integral fraction numerator x over denominator 1 minus x squared end fraction d x end exponent equals e to the power of negative open parentheses 1 divided by 2 close parentheses log open parentheses 1 minus x squared close parentheses end exponent equals fraction numerator 1 over denominator square root of 1 minus x squared end root end fraction end style"},"status":"ok"}