{"result":{"text":"From space the space straight F. straight B. straight D. space it space is space clear space that space we space get space the space equations comma space space space space\nmg space sin space straight theta space – space straight f space equals space ma space space space space\nfr space equals space Iα space\nequals I a over r open parentheses since space space straight alpha equals straight a over straight r close parentheses\nSolving\nstraight a equals fraction numerator mgsinθ over denominator straight m plus straight I over straight r squared end fraction semicolon space the space time space taken space by space the space bodies space to space roll space down space straight a space distance comma space straight l space is space square root of fraction numerator 2 l over denominator a end fraction end root.\nUsing space I equals 1 half m r squared space for space the space solid space cylinder space and space I equals 2 over 3 m r squared space for space the space space hollow space spherical space shell space we space get space the space required space result."},"status":"ok"}