{"result":{"text":"begin mathsize 14px style therefore P left parenthesis A intersection B right parenthesis equals fraction numerator integral subscript 0 superscript 1 square root of x d x minus integral subscript 0 superscript 1 x squared d x over denominator integral subscript 0 superscript 1 d x end fraction equals 2 over 3 minus 1 third equals 1 third end style"},"status":"ok"}