{"result":{"text":"therefore fraction numerator mu subscript 0 over denominator 4 pi end fraction fraction numerator 2 pi I subscript 1 over denominator R end fraction equals fraction numerator mu subscript 0 over denominator 4 pi end fraction I subscript 2 over R space space space space space space space space space o r space space space space space space space space space I subscript 1 over I subscript 2 equals fraction numerator 1 over denominator 2 pi end fraction"},"status":"ok"}